Hi everybody,
first of all excuse me for my English, I know it is not so good...
I have got an old good 1974 Stornello that is giving me trouble with the electric circuit.
It has been modified by the previous owner eliminating the battery and changing some connection on main switch.
In my opinion it can be used in daylight only cause the light are... let say...funny.
So I want to get back to the original but first i would like to fully understand the logic of the original circuit.
If I look at the original schematic (see picture) I get a bit confused mainly because is missing the internal schematic of the magneto and I can't really imagine how the switch is suppose to change connections in every position.
So I found in the net another schematic that is a title bit easier as far to imagine how main switch work even is rappresented separate in item 2 and 19 while in realty is in one block only.
I am reasoning on these and I will appreciate a lot if some kind guys follow me and tell where I am wrong:
So Item 19, quite simple, pushing down the key, from off to on, disconnect from the ground the gray generator cable from the ignition coil enabling spark.
In the mean time connect the negative pole of the battery to the frame (ground).
Horn and stop light are enabled if you push their switch.
Is that correct?
Now let see item 2.
I know that green and red cables from generator come from two different point of the same coil, giving different voltage; let say around 3.000 rpm 16 V the green and 8 V the red.
With key on, centre position engine running, green charge the battery trough blue passing a diode.
Since current from the diode is just half wave 16V AC seems to be more or less correct for the task of charging a 6V battery.
Same if you turn key to the right.
I suppose upper part of the rotor in the main switch turn together with the lower and is always connected with the yellow cable.
If so, turning key to right we light trough black and yellow cable, front and rear city light plus instrument if there are.
If we turn key to the left we switch off front city light ad send current to hi/low beam, depending on the position of external switch.
Up to now am I correct?
But what about battery? If we pass trough a single diode an 8V AC are we going to have enough voltage to charge the battery?
Plus in the previous case current come from fuse trough black cable and can be aided from battery, while in this case it come from generator trough red cable.
It can just go to the battery, if its voltage is high enough, but not get back due the diode.
The hi/low light are totally dependent on alternator and going up and down with engine RPM.
Now the questions:
It is supposed to be like this?
I will be tankful to everybody would be so kind to give me his opinion.
Ciao
Osvaldo